Find the scalar equation of the plane containing the points A(-3, 1, 1) and B(-4, 0, 3) and the vector u = [1, 2, 3]

Are my steps right?

Make one a point a vector. Cross the new vector with u. Then put it in scalar form with the remaining point?

Question

Find the scalar equation of the plane containing the points A(-3, 1, 1) and B(-4, 0, 3) and the vector u  = [1, 2, 3]

Are my steps right?

Make one a point a vector. Cross the new vector with u. Then put it in scalar form with the remaining point?

amistre64 · Answer

you cant simply make a point a vector.

a vector is defined by 2 points

amistre64 · Answer

the vector from B to A is:

  A(-3, 1, 1)
-B(-4, 0, 3) 
------------
      [1, 1,-2 ]

now you can cross that

amistre64 · Answer

once you have your crossed (normal vector) you can then attach it to a given point

anonymous · Answer

Yep that's what I meant. 7x+5y+11z-5 was my final answer. Is that correct?

amistre64 · Answer

x 1 1
y 2 1
z 3-2

x = -4-3
y = -(-2-3)
z = 1-2

[7, -5, 1]

unless i mis crossed; i would have to disagree with your results

amistre64 · Answer

7x - 5y + z + d = 0

such that d is the correct constant from the expansion stuff