State the horizontal asymptote of the rational function.
f(x) = (9x^2 - 3x - 8)/(4x^2 - 5x + 3)

Question

State the horizontal asymptote of the rational function.
f(x) = (9x^2 - 3x - 8)/(4x^2 - 5x + 3)

luigi0210 · Answer

anonymous · Answer

no like ive tried the problem a dozen times at least i just cant get the answer to be one of the choices...:(

anonymous · Answer

y = 3/5

 y = 9/4

 y = 0

 None

anonymous · Answer

those are the choices

luigi0210 · Answer

Well did you read the page? It explains it pretty well.

luigi0210 · Answer

In this example n=m, so that means the Horiz Asym: a/b

anonymous · Answer

yes i read it but im not the math brain so i need help

luigi0210 · Answer

When dealing with asym. you have to look at the exponents. So tell me are the exponents the same power?

anonymous · Answer

yes

luigi0210 · Answer

Good, so in case instead of it being that long equation it turns into this:
$$\frac{ 9x^2-3x-8 }{ 4x^2-5x+3 }=\frac{9x^2}{4x^2}=\frac{9}{4}$$

anonymous · Answer

oooooooh!!! i get it so its only the one with the exponent x's?

luigi0210 · Answer

If they have the same power. And only if those powers are also the higher ones.

anonymous · Answer

ok i get it! so it wouldnt work if it was like 9x^3 and 4x^2? and it would if both were x^5?

anonymous · Answer

(just examples to make sure)

luigi0210 · Answer

Here I'll show you:
$$\frac{x^2}{x^2}=\frac{1}{1}$$
$$\frac{x^3}{x^2}=slant $$
$$\frac{x}{x^2}= 0 $$

anonymous · Answer

ok thanks! :)

luigi0210 · Answer

No problem.