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OpenStudy (anonymous):
Solve using substitution:
3y − x − 1 = 0
- 4x = -6y
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OpenStudy (anonymous):
help please
OpenStudy (anonymous):
Pick one equation to solve for one variable. I suggest the first equation and solve for x because that choice will avoid fractions.
OpenStudy (anonymous):
i tried that but i didnt get the answer i needed
OpenStudy (anonymous):
What equation did you get?
OpenStudy (anonymous):
i got 3y-x=2 idk i cant seem to do because i dont know how
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OpenStudy (anonymous):
Go back to the first equation:
\[3y-x-1=0\]
and solve for x using inverse operations.
OpenStudy (anonymous):
Solve for x means to isolate x.
OpenStudy (anonymous):
Inverse operations means if a number is added, then subtract it from both sides.
If the number is being multiplied then divide it from both sides.
OpenStudy (anonymous):
so how do i get rid of y
OpenStudy (anonymous):
You don't get rid of it - you move it to the other side. The idea in this first step is to isolate x.
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OpenStudy (radar):
One way would be to add x to both sides of 3y-x-1=0
OpenStudy (anonymous):
so it would be 3y-1=0+x
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
You can drop the 0.
OpenStudy (anonymous):
ok so whats next
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OpenStudy (anonymous):
Now, replace the x in the other equation with everything that is x equals.
OpenStudy (radar):
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