Question

evaluate the improper integral from (negative infinity to 0) of 1/(3-4x)dx

Answer 1

\[\int\limits_{-\infty}^{0}\frac{1}{3-4x}dx\]

Answer 2

yes, thats it.

Answer 3

you can either integrate it (you will get a log function) or you can use a comparison test

Answer 4

i integrated it. I got 1/16Ln(3-4x)

Answer 5

why 16

Answer 6

sorry, it souled be (-1/4)ln(3-4x)

Answer 7

that is better

Answer 8

im not sure what the new limits of integration are....is it from t to 0?

Answer 9

\[\int\limits_{-\infty}^{0}\frac{1}{3-4x}dx\]

\[\lim_{t\to -\infty}\int\limits_{t}^{0}\frac{1}{3-4x}dx\]

\[\lim_{t\to -\infty}\left.-\frac{1}{4}\ln(3-4x)\right|_{t}^{0}\]

Answer 10

ok that makes sense now. Thanks alot

Answer 11

np