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(√32)^x = 4 How do I solve this?
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\[\sqrt{32}=(32)^{\frac{1}{2}}=((2)^5)^{\frac{1}{2}}=2^{\frac{5}{2}}\]
\[4=2^2\]
Put those facts together and solve the equation.
Oh. Thank you!
Wait I still don't understnad. This is what I did. I don't see what I'm doing wrong. 2^5^1/2 = 2^2 2^(5/2) = 2
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@Mertsj
Where did the x go?
IDK DX I don't know where it's supposed to be.
|dw:1374546040347:dw|
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