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Mathematics 11 Online
OpenStudy (anonymous):

help pleaseeeee

OpenStudy (anonymous):

OpenStudy (mathstudent55):

Equation of circle centered at \( (h, k) \) with radius \(r\). \( (x - h)^2 + (y - k)^2 = r^2 \)

OpenStudy (anonymous):

still confused

OpenStudy (mathstudent55):

Look at the graph. What is the center of the circle? What is the radius of the circle?

OpenStudy (anonymous):

0,0?

OpenStudy (mathstudent55):

Good. What about the radius?

OpenStudy (anonymous):

3

OpenStudy (mathstudent55):

Good. Now look again at the equation of a circle. You have all the information you need. \((x - h)^2 + (y - k)^2 = r^2\) The center is \( (h, k) = (0, 0)\), so \(h = 0\) and \(k = 0\). The radius is 3, so \(r = 3\). Now we plug these values in the equation: \((x - 0)^2 + (y - 0)^2 = 3^2\) Now we simplify: \(x^2 + y^2 = 3^2\) \(x^2 + y^2 = 9\) That's the final answer.

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