PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I WILL AWARD MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! What is the length of the major axis of the ellipse given by the equation? 8 9 16 18
\[(x^2/81)+(y^2/64)=1\]
@Loser66 @Hero @satellite73 @texaschic101
@satellite73 @satellite73 @satellite73 @satellite73
hi
HI
center of your ellipse is \((0,0)\) right?
if it is not in the question then it is not their.
i am telling you it is \((0,0)\) because the general form is \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] and is this case \(h=k=0\) so the center is \((0,0)\)
OH ok.
the major axis goes from \(-a\) to \(a\) here you have \(a^2=81\) so what is \(a\) ?
It is 9
is this the answer.
hold on
yes
it asks for the length of the major axis, which goes from \((-9,0)\) to \((9,0)\)
also I have ONLY ONE MORE QUESTION TO ASK YOU PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE
so the answer is NOT 9
OK so the answer can be found by using the distance formula?
it is 18 the length of the "semi major" axis is 9
you don't need the distance formula to find the distance between \((-9,0)\) and \((9,0)\)
|dw:1374547600823:dw|
lousy picture but you get the idea distance is \(18\)
yes of course.
ok i can help you with the next one as well
ok thanks also I found one more question after that.
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