Question

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I WILL AWARD MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

What are the foci of the ellipse given by the equation the quantity x minus 5 end quantity squared over 81 plus the quantity y plus 1 end quantity squared over 9 = 1?

(5, –1 ± 3square root of 10)

(5, –1 ± 6square root of 2)

(5 ± 3square root of 10, –1)

(5 ± 6square root of 2, –1)

Answer 1

@satellite73

Answer 2

@satellite73

Answer 3

Is this also complicated.

Answer 4

no this one is way way easier because you don't have to complete the square
it is already in the form you want

Answer 5

Oh ok thanx.

Answer 6

\[\frac{(x-h)^2}{a^2}+\frac{y-k)^2}{b^2}=1\] identify \(a, b\) and \((h,k)\)

Answer 7

UHHHHHHHHHHHHH????????

Answer 8

general form is
\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] you have something that looks just like it
you need to say what you have for \(a^2, b^2\) and \((h,k)\) the center

Answer 9

Oh I am sorry.

Answer 10

a=9 b=3 h=-5 k= 1

Answer 11

no actually \(h=5, k=-1\)

Answer 12

Oh but I was close.

Answer 13

so center is \((5,-1)\)

Answer 14

So it is??????????????????????????????

Answer 15

now what is \(\sqrt{81-9}\) ?

Answer 16

8.485281374

Answer 17

lol yeah, but you have radicals in your choices so you don't want a decimal approximation

Answer 18

THEN I DO NOT KNOW

Answer 19

{sqrt72}

Answer 20

you want
\[\sqrt{81-9}=\sqrt{72}=\sqrt{36\times 2}=\sqrt{36}\sqrt{2}=6\sqrt{2}\]

Answer 21

simplest radical form of \(\sqrt{72}\) is \(6\sqrt{2}\)

Answer 22

OH

Answer 23

so you have to go that many units to the left and right of the center \((5,-1)\)

Answer 24

So it is B this time am I rightam I rightam I rightam I rightam I rightam I rightam I rightam I rightam I right

Answer 25

no

Answer 26

left and right

Answer 27

DAME

Answer 28

not up and down

Answer 29

OH ok you lost me now.

Answer 30

try D