help me i need to pass my test PLease The first term of a geometric series is 3, and the sum of the first term and the second term is 15. What is the sum of the first six terms?
The first term is 3. The second term is 3 multiplied by the common ratio r. So we can write an equation from the given value of the sum of the first and second terms: 15 = 3 + 3r This equation can be solved to find the value of r. Can you do that?
r=4
What about terms 3-6?
Good work! Now that you have the value of r you can use the following formula to find the sum of the first six terms: \[S _{n}=\frac{a(r ^{n}-1)}{r-1}\]
28.2
a.1023 b.3906 C4096 d.11718 these are the options
2457
but its the choses i am given
Sorry, my bad. Substituting in the formula for the sum of n terms gives the following: \[S _{6}=\frac{3(4^{6}-1)}{4-1}=4^{6}-1=4095\]
thabks
You're welcome :)
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