Mathematics
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OpenStudy (anonymous):
If f(x)=x/9sqrt9+x^2 find f '(x) using derivatives
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OpenStudy (fibonaccichick666):
just to clarify is this the eq. \[f(x)=\frac{x}{9 \sqrt 9}+x^2\]
OpenStudy (anonymous):
sorry my pc died
OpenStudy (anonymous):
f(x)= x /(9)sqrt(9+x^2))
OpenStudy (fibonaccichick666):
it's cool my internet does it all the time
OpenStudy (fibonaccichick666):
ok so \(f(x)=\frac{x}{9 \sqrt (9+x^2)}\)
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OpenStudy (anonymous):
yes
OpenStudy (science0229):
If you simplify the equation, it becomes \[\frac{ 1 }{ 27 }x+x ^{2}\]
OpenStudy (anonymous):
i got (1/9) [(1)(9+x^2)]-(x)92x/sqrt9+x^2)/(9+x^2)^2
OpenStudy (anonymous):
it should say ....-(x)(2x/sqrt..
OpenStudy (psymon):
Just to clarify, we have x[(9√(9+x^2)] ?
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OpenStudy (fibonaccichick666):
I wrote it up top Psymon
OpenStudy (anonymous):
x/ [(9√(9+x^2)]
OpenStudy (fibonaccichick666):
so in order to solve this you have two main options, one you can reduce the fraction or two you can apply the quotient rule
OpenStudy (fibonaccichick666):
I am going to assume, the quotient rule is what your teacher is looking for
OpenStudy (fibonaccichick666):
So can you type it for me please?
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OpenStudy (anonymous):
??? f'g-fg'/g^2 ?
OpenStudy (psymon):
Yep yep
OpenStudy (anonymous):
(1/9) [(1)(9+x^2)]-(x)92x/sqrt9+x^2)/(9+x^2)^2 <-- i think its right
OpenStudy (fibonaccichick666):
Not quite
OpenStudy (fibonaccichick666):
So in our case, what is g(x)?
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OpenStudy (anonymous):
-(x)(2x... I made a typing mistake
OpenStudy (fibonaccichick666):
Still not quite, but what is f(x) as well?
OpenStudy (anonymous):
that it what confuses me since the demoninator says 9sqrt9+x^2 I am assuming that g shall be (9+x^2)
OpenStudy (fibonaccichick666):
that is where the confusion lies
OpenStudy (fibonaccichick666):
The g(x) is the entire bottom piece of the fraction so it is \(g(x)=9 \sqrt(9+x^2)\)
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OpenStudy (fibonaccichick666):
So next can you please find g'(x) showing all of your steps?
OpenStudy (anonymous):
ooooh (9)(1/2)(9+2x)? since the 9s dont have an x should I write that they =0?
OpenStudy (fibonaccichick666):
Not quite. Let me show you a similar ex. \[h(x)=8\sqrt(8+x^3)\]\[Let~u=8+x^3~~du=3x^2\]\[Then~we~have: ~~h(x)=8\sqrt u~du\]
OpenStudy (fibonaccichick666):
Whoops forget the du on the last part
OpenStudy (fibonaccichick666):
(also make the last part h(u)) ok so now, can you find the derivative of h(u)?
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OpenStudy (anonymous):
it should say 8/sqrt h(u)? is that what you meant?
OpenStudy (anonymous):
you are appliying the chin rule, right?
OpenStudy (fibonaccichick666):
no not h(u) I changed the variable, but yes chain rule.
OpenStudy (fibonaccichick666):
it should read \(h(u)=8\sqrt u\)
OpenStudy (anonymous):
8/sqrtu(u^1/2)
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OpenStudy (fibonaccichick666):
ok, not quite
OpenStudy (anonymous):
:(
OpenStudy (fibonaccichick666):
what is the derivative of √u?
OpenStudy (anonymous):
1/2u ^-1/2
OpenStudy (fibonaccichick666):
right
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OpenStudy (fibonaccichick666):
so d/dx(8√u)=?
OpenStudy (anonymous):
8(1/2)u^-1/2
OpenStudy (anonymous):
4u^-1/2
OpenStudy (fibonaccichick666):
yes! but one missing piece I asked for the derivative WRT x, so that means ...
OpenStudy (fibonaccichick666):
?