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Mathematics 10 Online
OpenStudy (anonymous):

Find the perimeter of the following polygon

OpenStudy (anonymous):

OpenStudy (anonymous):

@mayankdevnani

OpenStudy (anonymous):

@kropot72

OpenStudy (anonymous):

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OpenStudy (psymon):

You need the pythagorean theorem for this where you would say that a^2+b^2 = c^2. However this is only going to work with a right triangle, meaning we can only look at one half of your triangle at a time. So, looking at your triangle you can see that it is split into two triangles by half. That base is a length of 16, meaning each of the two triangles has a base of 8. That being said, we now have two of 3 sides that will allow us to use the pythagorean theorem formula listed. One of the triangles will have a 3rd side of 8^2 + 15^ = c^2. So c^2 = 64 + 225 = 289. so if I square root that to change c^2 to c, I will get c = 17. Now I have that one length of 17 and that long base length of 16. Since both triangles are exactly the same, that opposite site we did not look at is also a length of 17. So your perimeter is then the addition of 17 + 17 + 16 which = 50.

OpenStudy (anonymous):

perfect thanks

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