Question

Help Pleaseee!(: Been stuck on it for an hr now.

Give the acceleration of a=d^2s/dt^2, initial velocity, and initial position of a body moving on a coordinate line. Find the body's position at time t, When a=9.8, v(0)=-3, and s(0)=0.

Answer 1

How long have you been suck on it for?

Answer 2

An hour now.. and I have no idea how to go about doing this problem lol

Answer 3

the joke was you said suck instead of stuck , and then I asked you again using the word suck in place of stuck

Answer 4

ohhhh... lol okay fixing that now..

Answer 5

s=ut+1/2at^2

Answer 6

I don't get that that function represents? @Krishnadas

Answer 7

ok ...i will tell you @pdd21

Answer 8

(:

Answer 9

ok..i dont know if this helps..but this is one way to the answwer

Answer 10

have you studies that equation in Physics?

Answer 11

*studied

Answer 12

@pdd21

Answer 13

you here?

Answer 14

@pdd21 need you here dude

Answer 15

?????????

Answer 16

reply......:(

Answer 17

sorry... got distracted trying the problem out again.. and i haven't studied the equation in physics.

Answer 18

ok i will help

Answer 19

let acceleration=a,u=initial velocity,and V =velocity at time t..okay?

Answer 20

a=dv/dt

Answer 21

dv=adt

Answer 22

integrate both sides \[\int\limits_{u}^{v}dv=\int\limits_{0}^{t}a dt\]

Answer 23

I havent really learned how to integrate yet, so it would be weird if I used it to show my work on this problem lol

Answer 24

that will be a problem..But i can show you how we got that equation

Answer 25

okay..(:

Answer 26

aint there a way to anti derive? its the same as integrating right?

Answer 27

ya..integration=finding anti derivate

Answer 28

so when time changes from 0 to t,velocity changes from u to V..you got this idea?

Answer 29

yup!

Answer 30

then you know nothing abt integration??

Answer 31

yup! lol... I'm pretty much having a hard time with this stuff lol