Ask your own question, for FREE!
Chemistry 20 Online
OpenStudy (anonymous):

Net Ionic equation for Ag+Na2CO3=

OpenStudy (anonymous):

net ionic eqtn is; 2Ag+ + (CO3) -2 -----> Ag2CO3 Ionic eqtn involves only the precipitated salt only...

OpenStudy (anonymous):

How about Pb+NaCl=

OpenStudy (anonymous):

Pb2+(aq) + 2Cl-(aq) --> PbCl2(s

OpenStudy (anonymous):

what happens to the Na?

OpenStudy (anonymous):

its half of two Pb(No3)2 + 2 NaCl = PbCl2 + 2 NaNo3 sum of charges must be the same on both sides and on both sides sum of charges must be zero

OpenStudy (anonymous):

How about Sb+Na2S=

OpenStudy (chmvijay):

2 Sb + 3 Na2S = Sb2S3 + 6 Na sory these are displacement reaction the first one also the same :)

OpenStudy (anonymous):

2 Sb + 3 Na2S = Sb2S3 + 6 Na is this correct

OpenStudy (anonymous):

oh yes it is @chmvijay write it

OpenStudy (anonymous):

So whay on the last the ionic equations does the NA stay - but in the first (Ag+Na2CO3) does the Na go away?

OpenStudy (chmvijay):

not its not true it wont go away 2Ag+ + Na2(CO3) -2 -----> Ag2CO3 +2Na

OpenStudy (anonymous):

but that was the ionic equation not balanced

OpenStudy (anonymous):

@Jerseygirle r u asking 4 ionic equation or balanced

OpenStudy (anonymous):

I need balanced net ionic equations

OpenStudy (chmvijay):

i have already given right

OpenStudy (anonymous):

How about for Pb+NaCl=

OpenStudy (anonymous):

Pb + 2 NaCl = Pb(NaCl)2

OpenStudy (chmvijay):

Pb+2NaCl=Pbcl2 +2Na

OpenStudy (anonymous):

So when I mix Ca and Na2S in a beaker there is no chemical reaction - why is this - and do I still have to make a chemical formula?

OpenStudy (chmvijay):

nope

OpenStudy (anonymous):

why not?

OpenStudy (chmvijay):

bcoz it may need different reaction conditions :)

OpenStudy (chmvijay):

to occur reaction :) do u want ot write equation u can since ur not getting ur desired product i though u no need to write

OpenStudy (anonymous):

so would I just write Ca+Na2S and not combine the reaction?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!