so you have
18 - 10\(\sqrt{3}\) + 9\(\sqrt{3}\) -15
OpenStudy (ivettef365):
can you take it from there
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OpenStudy (anonymous):
:/
OpenStudy (ivettef365):
just combine like terms
OpenStudy (anonymous):
3- sqrt3
OpenStudy (ivettef365):
correct
OpenStudy (anonymous):
Choose the system of equations which matches the following graph.
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OpenStudy (anonymous):
OpenStudy (anonymous):
x + 2y = 4
3x – 6y = 18
x – 2y = 4
3x + 6y = 18
x + 2y = 4
3x + 6y = 18
x – 2y = 4
3x – 6y = 18
OpenStudy (anonymous):
wont they be negative?
OpenStudy (ivettef365):
it can not be a, because when you convert to y = mx + b, where m = slope
you can see that both lines have negative slope and are parallel, so the slope needs to be negative and the same.
you have on a) x + 2y = 4
2y = -x + 4
y = -1/2x +2
and 3x - 6y = 18
-6y = -3x + 18 (divide by -6) you have
y = 1/2 x - 3
one have slope of -1/2 the other slope of 1/2 not good
OpenStudy (anonymous):
d then
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OpenStudy (ivettef365):
no, lets try c
x + 2y = 4
2y = -x + 4
y = -1/2x + 2 (y-int = 2) negative slope is good
3x + 6y = 18
6y = -3x + 18
y = -1/2x + 3 (negative slope, same slope, y-int = 3) is good
OpenStudy (anonymous):
oh ok :) im so dumb
OpenStudy (ivettef365):
no, you're not, is just a matter of practice
OpenStudy (anonymous):
What is the slope of the line which passes through (–2, 0) and (0, 4)?
how about this
OpenStudy (anonymous):
–2
0
2
Undefined
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OpenStudy (anonymous):
is it d
OpenStudy (ivettef365):
that is just using the slope formula
y2 - y1
------
x2 - x1