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Mathematics 8 Online
OpenStudy (anonymous):

The price p and the quantity x sold of a certain product obey the demand equation x=-20p+500, 0≤p≤25 a.Express the revenue R as a function of x. (Hint: R = xp, where p is the unit price.) b.What is the revenue if 20 units are sold? c.How many of this item should be sold in order to get maximum revenue? d.What is the maximum revenue? e.The marginal revenue. f.The marginal revenue at x = 100 @dumbcow

OpenStudy (dumbcow):

for a) revenue needs to be function of "x" so you need to solve the demand equation for "p"

OpenStudy (anonymous):

yes how do i go about it,

OpenStudy (dumbcow):

algebra...move things to other side of equal sign until "p" is isolated -subtract 500 -divide by -20

OpenStudy (anonymous):

im ot -1x/20 +25/10 is it right?

OpenStudy (anonymous):

got

OpenStudy (anonymous):

oh wait a min

OpenStudy (anonymous):

x/20-25 is what i got

OpenStudy (dumbcow):

you almost have it....-x/20 + 25

OpenStudy (dumbcow):

wait you changed the signs haha, you had it right before

OpenStudy (anonymous):

lol.im figuring out where the mistake is from

OpenStudy (anonymous):

ok got it now..wat do i do next

OpenStudy (dumbcow):

multiply that by "x" to get revenue R(x) = x*p(x)

OpenStudy (anonymous):

where x=-20p + 500 ??

OpenStudy (anonymous):

or where x is x? lol

OpenStudy (dumbcow):

haha x is x p = -x/20 + 25

OpenStudy (anonymous):

so that means the demand equation where x= -20p +500 is no longer to be used in question a?

OpenStudy (anonymous):

therefore R(x) =-1x^2/20+25x right

OpenStudy (dumbcow):

correct , its still the demand equation we just changed how it looked so everything is in terms of "x" not "p"

OpenStudy (anonymous):

ok.so my R(X) IS -1x^2/20+25x

OpenStudy (dumbcow):

yep, part b) plug in x=20 to find revenue

OpenStudy (anonymous):

IN THE R FUNCTION WE GOT?

OpenStudy (anonymous):

@dumbcow

OpenStudy (dumbcow):

yeah thats revenue

OpenStudy (anonymous):

oh ok..

OpenStudy (anonymous):

i got 480

OpenStudy (dumbcow):

yep

OpenStudy (anonymous):

is c asking for the vertex?

OpenStudy (dumbcow):

to get max revenue, set derivative equal to 0 yes find the vertex, but since you know calculus i would just take derivative

OpenStudy (anonymous):

ok let me work it out and tell you what i got now

OpenStudy (anonymous):

is 250 the answer

OpenStudy (dumbcow):

very good...then for part d) just plug that (x=250) into revenue function

OpenStudy (anonymous):

ok a sec

OpenStudy (anonymous):

i had 5937.5 is it right?

OpenStudy (anonymous):

ok i got it now

OpenStudy (anonymous):

i dont have to get a decimal

OpenStudy (dumbcow):

i get 3125

OpenStudy (anonymous):

yes 3125

OpenStudy (anonymous):

made a childish mistake earlier..llol

OpenStudy (dumbcow):

lol no problem part e) is easy its just the derivative you did earlier

OpenStudy (anonymous):

ok let me work it out.

OpenStudy (anonymous):

-2x +25 ?

OpenStudy (anonymous):

oops not again i omiiitted the 20

OpenStudy (anonymous):

-x/10 +25 right

OpenStudy (anonymous):

and f) is 15

OpenStudy (anonymous):

@dumbcow

OpenStudy (dumbcow):

sorry correct on both :)

OpenStudy (anonymous):

oh no need for sorry.

OpenStudy (anonymous):

and my last question .i told u i got two lol

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