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Mathematics 16 Online
OpenStudy (jazzyfa30):

help please work attached

OpenStudy (jazzyfa30):

OpenStudy (jdoe0001):

direct variation means, something varies proportionally to something else as this varies, that will vary at some proportion so if the atmospheric pressure in water increases by 4.3lbs for every square inch that means that 4.3lbs is your proportion, or your ratio, thus y = 4.3x if x = varies to 2, y varies to 4.3(2) = 8.6 if x = varies to 7, y varies to 4.3(7) = 30.1 and so on

OpenStudy (jazzyfa30):

ok

OpenStudy (jazzyfa30):

umm i just got super confused when i put it in

OpenStudy (jazzyfa30):

pleaseeeee helppppppppppppppppppppppppp

OpenStudy (johnweldon1993):

Well you need to figure out the general formula... Direct Vairation: Pressure varies with depth...so \[\large P = kd\] You have a 'P' and you have a 'd' ....you need to solve for 'k' \[\large 4.3 = k(10)\] \[\large k = ?\] After you solve for 'k'....you write your equation that you know can use to solve any depth... \[\large y = (\text{Enter 'k' here})x\]

OpenStudy (jazzyfa30):

so i do 4.3*10

OpenStudy (jazzyfa30):

or 4.3/10

OpenStudy (johnweldon1993):

Right Divided...because you need to solve for 'k'...so what is 4.3/10?

OpenStudy (jazzyfa30):

ok so k=.43

OpenStudy (johnweldon1993):

Right...so your equation that you would want would be... \[\large P = 0.43d\] where 'P' is pressure and 'd' is depth

OpenStudy (jazzyfa30):

so my answer is p=0.43d

OpenStudy (johnweldon1993):

Well yeah...because the picture shows...at 10 depth units...the pressure = 4.3 psi...so .43 * 10 DOES = 4.3.....so yes your answer would be that :)

OpenStudy (jazzyfa30):

ok can u help with a few more and thanks

OpenStudy (johnweldon1993):

I actually have to go for a little bit...if you still need help a little later on and you see I'm on again....feel free to message me if you want :)

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