Two forces of 250 N and 575 N act on an object. The angle between them is 60 degrees. Determine the magnitude and the direction of the resultant force relative to the 250 N force.

Question

anonymous · Answer

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anonymous · Answer

So how would I start solving the problem?

anonymous · Answer

OK, I'm going to guess. Will it be as simple as adding two vectors?

anonymous · Answer

So,

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F1 = 250 N

F2 = 575 N

f1x = 250N

f1Y = 0

F2x = 575cos60

f2y = 575sin60

fx = (250N + 575cos60) = 537.5N [E]
fy = (0+ 575sin60) = 497.96 N [N] 

angle = arc tan (497.96/537.5)

fnet = Sqrt*((fx^2 +fy^2)) = 732.72 N [41.8 N of E]