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Mathematics 7 Online
OpenStudy (anonymous):

Identify the asymptotes of y= 1 / (4x-4) + 3 (multiple choice..A, B, C or D) please & thank you? :) A: Vertical asymptote: x=1, Horizontal asymptote: y=3. B. Vertical asymptote: x=-1, Horizontal asymptote: y=-3. C. Vertical asymptote: x=3, Horizontal asymptote: y=1. D. Vertical asymptote: x=1/4, Horizontal asymptote: y=-3.

OpenStudy (anonymous):

honestly dont understand how to find the answer on the graph...

OpenStudy (primeralph):

@satellite73

OpenStudy (anonymous):

ok lets go slow

OpenStudy (primeralph):

I actually meant "zoom in and adjust". @satellite73 Will handle this.

OpenStudy (anonymous):

you are looking for two different kinds of asymptotes, a "vertical" asymptote and a "horizontal" asymptote lets find the vertical one first

OpenStudy (anonymous):

\[y=\frac{1}{4x-4}+3\] will have a vertical asymptote where the expression is undefined, i.e. where the denominator is zero solve \(4x-4=0\) for \(x\) what do you get?

OpenStudy (anonymous):

x=1 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so the vertical asymptote is the vertical like \(x=1\)

OpenStudy (anonymous):

the horizontal asymptote is \(y=3\) because of the \(+3\) hanging out at the end of \(y=\frac{1}{4x-4}+3\)

OpenStudy (anonymous):

oh.. that makes sense.

OpenStudy (anonymous):

good that is all there is to it

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