f(x)=x^(3)/(x^(2)-4)

what interval contains a local maximum for the function above.

Question

f(x)=x^(3)/(x^(2)-4)

what interval contains a local maximum for the function above.

anonymous · Answer

$$f(x)=\frac{x^3}{(x+2)(x-2)}$$ ?

anonymous · Answer

$$f(x)=x^3/(x^2-4)$$

anonymous · Answer

same thing
calc class or algebra?

anonymous · Answer

algebra

anonymous · Answer

ok you need to graph then
you have to vertical asymptotes at $x=-2$ and $x=2$

anonymous · Answer

in the middle it goes from $\infty$ to $-\infty$ so no max on $(-2,2)$

anonymous · Answer

to the left of $-2$ it goes up and then down, so that is the interval that will have a local max 
to the right of $2 $ it goes down and then up, that is the interval that will have a local min

anonymous · Answer

A. (0,2)
B. (-(infinity), -2)
C.(-2,0)
D.(2, (infinty)

These are my answer choices

anonymous · Answer

did you understand what i wrote?  the answer is there

anonymous · Answer

no i do not understand it.

anonymous · Answer

(-2,0)?

anonymous · Answer

@satellite73

anonymous · Answer

no the interval will be $(2,\infty)$ on which there will be a minimum

anonymous · Answer

here is a picture, you can see why this is true http://www.wolframalpha.com/input/?i= \frac{x^3}{%28x%2B2%29%28x-2%29}