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Mathematics 14 Online
OpenStudy (anonymous):

Chain Rule Question Using the equation below, use the chain rule on r(t)= to show the speed is given by S(t)=u'(t)√(f' (u)^2+g' (u)^2 ) I know how the chain rule works: f'[g(x)]*g'(x) I understand if you take the derivative of both you would get f'(u(t))*u'(t) and same for the g portion g'(u(t))*u'(t) Not sure how that applies to the speed, the formula they give looks like u'(t) has been factored out and then a distance formula. @FibonacciChick666 @dumbcow

OpenStudy (anonymous):

To make it easier to read the starting equation is: \[r(t) = <f(u(t)),g(u(t))>\] The equation we're trying to get to is: \[S(t) = u'(t)\sqrt{f'(u)^{2}+g'(u)^{2}}\]

OpenStudy (primeralph):

The major thing here is arc length. Ever heard of that?

OpenStudy (primeralph):

@Charollete

OpenStudy (primeralph):

@sarahusher Can you finish this?

OpenStudy (anonymous):

Yeah. I was going to mention that in my main question, it looks like arc length which is the integral of that I believe.

OpenStudy (primeralph):

Something like that. Apply the arc length definition and you should get the answer.

OpenStudy (anonymous):

Ahh, so instead of working forward, work backwards from the speed by integrating.

OpenStudy (primeralph):

Not really working backwards. Hold on.

OpenStudy (fibonaccichick666):

r(t) is a position function correct?

OpenStudy (anonymous):

Yes I believe so

OpenStudy (primeralph):

In my opinion, S is usually arc length, which would make sense here. V is speed mostly.

OpenStudy (anonymous):

well the question says Use the Chain Rule to show that the speed is given by \[S(t) = u'(t)\sqrt{f'(u)^{2}+g'(u)^{2}}\]

OpenStudy (anonymous):

but it looks similar to arc length.

OpenStudy (primeralph):

@mathstudent55 I'm tired. Please handle this.

OpenStudy (anonymous):

S is primarily used to denote arc length, I have never seen it to denote speed... is it possible that there is just a typo in the question?

OpenStudy (primeralph):

Or we're all just too old to remember basic calculus.

OpenStudy (anonymous):

The question says use the Chain Rule to show that the speed is given by the 2nd equation above.

OpenStudy (primeralph):

@sarahusher Is very smart. She'll help you. I'm going to bed.

OpenStudy (anonymous):

I'm with you guys though it does look as if its arc length. but the given function is for a trajectory, so I'm assuming you can basically show steps on how to get to that second equation, and with it then find the speed? Thanks @primeralph have a good night.

OpenStudy (primeralph):

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