Question

If a,b,c are in A.P. prove that a^2+c^2+4ac=2(ab+bc+ca)
now as a,b,c are in AP b-a=c-b or 2b = a+c, but can't proceed further..

Answer 1

I'm not sure if I can help... What is the AP set?

Answer 2

@terenzreignz : could you please help me with this ?

Answer 3

Interesting how they contain squares...
have you tried squaring both sides of
2b = a+c ?

Answer 4

add b^2 on both the side and move the right side to left..you can see (a-b+c)^2=b^2

Answer 5

This is going to take some creativity...which I lack :D hang on

Answer 6

so @ankit042 both sides will equate to b^2

Answer 7

Yeah you have to show L.H.S = R.H.S

Answer 8

thanks @ankit042