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Mathematics 18 Online
OpenStudy (anonymous):

sjld

OpenStudy (anonymous):

@sarahusher

OpenStudy (anonymous):

So for example take polynomial \[p(x)=4x ^{3}+12x^{3}+8x\] and let monomial \[m(x)=4x\] where a monomial is a polynomial with one term and rational coefficients if you have \[\frac{ p(x) }{ m(x) } =\frac{ 4x ^{3}+12x ^{2}+8x }{ 4x } \] You can prove the quotient in two ways: 1) long division 2) cancellation rule That is the approach I would take to this question :)

OpenStudy (anonymous):

@sarahusher can I use this example as my answer? :/

OpenStudy (anonymous):

You can if you want, but I think it would be good practice to come up with one as well so you understand how it works :)

OpenStudy (anonymous):

@sarahusher ookay :) thank you so much!!

OpenStudy (anonymous):

No problem :) let me know if you come up with another example and I can check it for you!

OpenStudy (anonymous):

@sarahusher okay is long division where you take the numerators and divide them all by the denominator? & subtract the exponents? What's the cancellation rule? :0

OpenStudy (anonymous):

yes! that is long division The cancellation rule is just where you try to factorise out common factors so that you get the simplest form :)

OpenStudy (anonymous):

okay & how do you do that with that example problem you showed me above? I did the long division but I've never done the cancellation rule before :/ i feel dumb lol @sarahusher

OpenStudy (anonymous):

okay, so put the bigger number on top, the little one below so we get \[\frac{ 4x ^{3}+12x ^{2}+8x }{ 4x } = \frac{ 4x(x ^{2}+3x+2) }{ 4x(1) }=\frac{ 4x }{ 4x }\times \frac{ x ^{2}+3x+2 }{ 1 }\] \[= 1\times( x ^{2}+3x+2)=(x+2)*(x+1)\]

OpenStudy (anonymous):

and don't feel dumb :) practice makes perfect!

OpenStudy (anonymous):

@sarahusher :) omg you're a lifesaver!! thank youuu!

OpenStudy (anonymous):

ha no problem dear, just keep practising :)

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