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\[\log_{x} 25=2\] Find x
well its reasonably easy raise each side as a power of x \[a^{\log_{a}(x)} = x\] so using the log law 25 = x^2 it should be obvious.... but if not, take the square root of both sides.
So 5=x?
yep... nice and neat
Oh, I guess I was over thinking it.
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it just asked you to raise the log as a power of the base... which needed to be done to both sides of the equation.
Do the same concept with this one? \[\log_{2} x=5\]
So, Like this. \[a^{\log_{2} } \]
=5
not quite its \[a^{\log_{a}(b)} = b\]
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Then what? I'm confused with this one.
ok, |dw:1374664296222:dw|
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