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Algebra 8 Online
OpenStudy (anonymous):

Assistance Needed.

OpenStudy (anonymous):

\[\log_{x} 25=2\] Find x

OpenStudy (campbell_st):

well its reasonably easy raise each side as a power of x \[a^{\log_{a}(x)} = x\] so using the log law 25 = x^2 it should be obvious.... but if not, take the square root of both sides.

OpenStudy (anonymous):

So 5=x?

OpenStudy (campbell_st):

yep... nice and neat

OpenStudy (anonymous):

Oh, I guess I was over thinking it.

OpenStudy (campbell_st):

it just asked you to raise the log as a power of the base... which needed to be done to both sides of the equation.

OpenStudy (anonymous):

Do the same concept with this one? \[\log_{2} x=5\]

OpenStudy (anonymous):

So, Like this. \[a^{\log_{2} } \]

OpenStudy (anonymous):

=5

OpenStudy (campbell_st):

not quite its \[a^{\log_{a}(b)} = b\]

OpenStudy (anonymous):

Then what? I'm confused with this one.

OpenStudy (loser66):

ok, |dw:1374664296222:dw|

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