A ball is dropped from the top of a 550 ft. building. The function models the height of the ball, h(t) (in feet), at any given time, t (in seconds).
How long does it take the ball to reach the ground? Round your answer to the nearest hundredth of a second. @xoya @dan815 @ankit042

Question

A ball is dropped from the top of a 550 ft. building.  The function  models the height of the ball, h(t) (in feet), at any given time, t (in seconds).
How long does it take the ball to reach the ground?  Round your answer to the nearest hundredth of a second. @xoya @dan815 @ankit042

anonymous · Answer

@dan815  :)

ankit042 · Answer

you know the trajectory of the ball?

anonymous · Answer

no.

ankit042 · Answer

ball is dropped straight and gravity will be accelerating the ball. it starts with initial speed of 0

ankit042 · Answer

s= ut+(1/2)at^2 ...heard of this formula

anonymous · Answer

I remember seeing it before, i just never applied it to any problems

ankit042 · Answer

This can be your first time! here u=0 and you can use a as 9.8m/s^2

anonymous · Answer

okay where did the 9.8 come from.

ankit042 · Answer

9.8 is the standard acceleration from gravity

anonymous · Answer

Umm.. ok... wow. confused much. lol.. i really dont understand what to do with the equation .

ankit042 · Answer

550 = (1/2)*9.8t^2 solve!

anonymous · Answer

okay i got 10.59,-10.59

ankit042 · Answer

Great! Hope you understood this

anonymous · Answer

Thank you so much.