How do you find the value of df^-1/dx at x = f(a)? f(x) = 5x + 10, a = 4
first find f(a)
then just plug it in
f(a)=5a+10 and u know that a=4
so f(a)=30
Which means x=30
Is that \[\frac{ df ^{-1} }{ dx }\]?
Are there any parentheses around df?
so that means u can put the f in the denominator
and by the way wtf is f? do u mean the inverse of f(x)?
not sure, I copied and pasted it straight off of the homework sheet, so I'm going out on a limb and assuming that it means inverse of f
not sure what just happened there, this thing just posted all of my previous posts over again
can u like screenshot ur hw sheet? it just says f^-1?
it says what you have posted up there\[df^-1/dx \] it's number 10 and then also the same process for number 11
ya my computer cant read that right so find the inverse of f(x). You know how to do that? Just solve x=5y+10 for y and that will be f^-1(x)
then once u have that substitute it in the equation for f^-1(x) and we already found out that x=30
wait a minute wtf is d
what does the question say
find the value of df^-1/dx at x = f(a) f(x) = 5x + 10, a = 4
BRB
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