Question

factor completely:
16y^2+40xy+25x^2

Answer 1

16y^(2)+40xy+25x^(2)

For a polynomial of the form ax^(2)+bx+c, find two factors of a*c (400) that add up to b (40).
a=16, b=40, c=25

For a polynomial of the form ax^(2)+bx+c, find two factors of a*c (400) that add up to b (40).In this problem (5)/(4)*(5)/(4)=(25)/(16) (which is (c)/(a)) and (5)/(4)+(5)/(4)=(40)/(16) (which is (b)/(a)) , so insert (5)/(4) as the right hand term of one factor and (5)/(4) as the right-hand term of the other factor.
(y+(5)/(4)*x)(y+(5)/(4)*x)

Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(4y+5x)(4y+5x)

Combine the two common factors of (4y+5x) by adding the exponents.
(4y+5x)^(2)

Answer 2

isn't there an equation for this so its shorter?

Answer 3

(4y+5x)^(2)

Answer 4

sorry, i actually meant something like how a^2-b^2= (a+b)(a-b) but for this problem?

Answer 5

if that makes sense

Answer 6

i know one half of it goes a^2+2ab+b^2 if that applies.