find the angle measures of the quadrilateral (pic show)
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Theorem: If a quadrilateral is inscribed in a circle, then opposite angles of the quadrilateral are supplementary. <B and <D are opposite angles. <B and <D are supplementary So, z/2 + (z/4) + 30 = 180 Solve for z @ineedhelpinmath08
thats what im starting off with .. im just confused on whether i should subtract 30 from 180 or ?
Yes, do that >> subtract 30 from 180 Post what you get: z/2 + (z/4) = ?
=150
Carry the equation along: z/2 + (z/4) = 150 Now, multiply each term (all 3 of them) by 4 to clear the fractions. Post what you get.
oooh okay
2z=600?
or 3z=600?
4 * z/2 +4* (z/4) =4* 150 2z + z = 600 so which is it, 2z = 600 or 3z = 600?
3z=600 sometimes when i do it in my head i miss something
z=200 then you plug themback into the equations to get the angles
but angle c cant be 200?
Suggestion: Don't do math in your head. Writing it is better. (my opinion)
it is i agree with you
>but angle c cant be 200? That is true. z = 200. Angle C is opposite Angle E. They are supplementary. So, get the measure of Angle E and subtract it from 180 to get the measure of angle C.
angle E is 141. 141-180 = 39
thank you so much for all your help!
well it should be 180-141=39 my bad
141-180 = -39 180 - 141 = 39 Subtraction is not commutative. Order matters.
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