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Mathematics 11 Online
OpenStudy (anonymous):

find the angle measures of the quadrilateral (pic show)

OpenStudy (anonymous):

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Directrix (directrix):

Theorem: If a quadrilateral is inscribed in a circle, then opposite angles of the quadrilateral are supplementary. <B and <D are opposite angles. <B and <D are supplementary So, z/2 + (z/4) + 30 = 180 Solve for z @ineedhelpinmath08

OpenStudy (anonymous):

thats what im starting off with .. im just confused on whether i should subtract 30 from 180 or ?

Directrix (directrix):

Yes, do that >> subtract 30 from 180 Post what you get: z/2 + (z/4) = ?

OpenStudy (anonymous):

=150

Directrix (directrix):

Carry the equation along: z/2 + (z/4) = 150 Now, multiply each term (all 3 of them) by 4 to clear the fractions. Post what you get.

OpenStudy (anonymous):

oooh okay

OpenStudy (anonymous):

2z=600?

OpenStudy (anonymous):

or 3z=600?

Directrix (directrix):

4 * z/2 +4* (z/4) =4* 150 2z + z = 600 so which is it, 2z = 600 or 3z = 600?

OpenStudy (anonymous):

3z=600 sometimes when i do it in my head i miss something

OpenStudy (anonymous):

z=200 then you plug themback into the equations to get the angles

OpenStudy (anonymous):

but angle c cant be 200?

Directrix (directrix):

Suggestion: Don't do math in your head. Writing it is better. (my opinion)

OpenStudy (anonymous):

it is i agree with you

Directrix (directrix):

>but angle c cant be 200? That is true. z = 200. Angle C is opposite Angle E. They are supplementary. So, get the measure of Angle E and subtract it from 180 to get the measure of angle C.

OpenStudy (anonymous):

angle E is 141. 141-180 = 39

OpenStudy (anonymous):

thank you so much for all your help!

OpenStudy (anonymous):

well it should be 180-141=39 my bad

Directrix (directrix):

141-180 = -39 180 - 141 = 39 Subtraction is not commutative. Order matters.

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