Mathematics
8 Online
OpenStudy (jazzyfa30):
(6y2 -6/ 8y2 +8y)/(3y -3 / 4y2 + 4y)
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OpenStudy (luigi0210):
Easy, flip and multiply
OpenStudy (jazzyfa30):
???????
OpenStudy (anonymous):
flip the second one and multiply
OpenStudy (jazzyfa30):
?????
OpenStudy (anonymous):
6y2-6/8y2+8y x 4y2+4y/3y-3
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OpenStudy (luigi0210):
\[\frac{6y^2-6}{8y^2+8y}*\frac{4y^2+4y}{3y-3}\]
OpenStudy (anonymous):
u can cross out 8y2 and change it to 2 and cross out the 4y2 completely
OpenStudy (anonymous):
same with 8y and 4y
OpenStudy (anonymous):
u also cancel out the 6y2 and make it 2y because 6/3= 2 and the y2 took the y on the bottom.
OpenStudy (anonymous):
and so ur left with 2y-2/2+2:
2y-2/4
simplify that and u get 1/2y-1/2
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OpenStudy (jazzyfa30):
ummmmm thats wrong
OpenStudy (luigi0210):
@nickirivera stop >.>
OpenStudy (jazzyfa30):
thats wrong
OpenStudy (jazzyfa30):
help please
OpenStudy (luigi0210):
Okay hold on
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OpenStudy (luigi0210):
\[\frac{6y^2-6}{8y^2+8y}*\frac{4y^2+4y}{3y-3}=\frac{6(y^2-1)}{8(y^2+1)}*\frac{4y(y+1)}{3(y-1)}\]
OpenStudy (luigi0210):
Can you finish it?
OpenStudy (jazzyfa30):
ummmm i think the answer 1
OpenStudy (luigi0210):
\[\frac{6(y+1)}{8(y^2+1)}*\frac{4y+1}{3}\]
That equals 1?
OpenStudy (luigi0210):
You were right, nice job Jazzy! :)
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OpenStudy (jazzyfa30):
the answer was wrong
OpenStudy (luigi0210):
Darn I see where I messed up.
OpenStudy (luigi0210):
\[\frac{6(y+1)}{8(y^2+1)}*\frac{4y(y+1)}{3}\]
OpenStudy (luigi0210):
Now simplify:
\[\frac{2(y+1)}{2(y^2+1)}*\frac{y(y+1)}{1}=\frac{y+1}{y^2+1}*y(y+1)\]
OpenStudy (jazzyfa30):
ummmmmm idk
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OpenStudy (luigi0210):
@nickirivera Is my process right? I need your feedback please.
OpenStudy (anonymous):
ohhhhh, lol, oki, yea hes right.. *props @luigi*
OpenStudy (luigi0210):
Thanks Nicki!
OpenStudy (anonymous):
ur welcome
OpenStudy (jazzyfa30):
hello