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OpenStudy (anonymous):
Find the value of cos^2 15 exactly
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OpenStudy (luigi0210):
\[\cos^2 15\]
That?
OpenStudy (anonymous):
yea
OpenStudy (callisto):
Let A = 15
cos A = cos 15
cos (2A) = cos (2x15) = cos 30.
Do you know what cos 30 is?
OpenStudy (anonymous):
sqrt(3)/2
OpenStudy (anonymous):
then what??...
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OpenStudy (callisto):
Use the identity:
\[cos2A = 2cos^2A -1\]to get \(cos^2A\)
OpenStudy (anonymous):
so is the answer sqrt(3) + 2?
OpenStudy (callisto):
Maybe you'd like to check your calculations again.
OpenStudy (anonymous):
ok can you do it for me?
OpenStudy (callisto):
No, but I don't mind checking it for you.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so you go:\[\frac{ \sqrt{3} }{ 2 } + 1 = 2 \cos^2 \]
OpenStudy (anonymous):
then\[\frac{ (\frac{ \sqrt{3} }{ 2 } + 1) }{ 2 } = \cos^2 A\]
OpenStudy (anonymous):
then what after that?
OpenStudy (callisto):
Almost there.
Simplify \(\frac{ (\frac{ \sqrt{3} }{ 2 } + 1) }{ 2 }\)
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OpenStudy (anonymous):
so sqrt(3) + 1?
OpenStudy (callisto):
No.
OpenStudy (anonymous):
sqrt(3) + 2?
OpenStudy (callisto):
No...
OpenStudy (anonymous):
then how
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OpenStudy (callisto):
\[\frac{ (\frac{ \sqrt{3} }{ 2 } + 1) }{ 2 } = (\frac{ \sqrt{3} }{ 2\times2 } + \frac{1}{2}) \]You may want to further simplify it.
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