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Mathematics 18 Online
OpenStudy (anonymous):

find angle g rounded to the nearest degree

OpenStudy (anonymous):

|dw:1374717147234:dw|

OpenStudy (anonymous):

\[\large\sin(g)=\frac{15}{17}\] \[\large g=\sin^{-1}(\frac{15}{17})\] and a calculator set in degree mode

OpenStudy (anonymous):

where it says "convert from radians to degrees" in this link http://www.wolframalpha.com/input/?i=arcsin%2815%2F17%29

OpenStudy (anonymous):

ohhh ok i get it!! my calculator wasnt in degrees!

OpenStudy (anonymous):

yeah that is a big problem, switching back and forth but a clue is when you get something like \(.7268\) instead of something like \(12.46\)

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

since you are on a computer, you might as well use wolfram like the link i sent that way you get them both yw

OpenStudy (anonymous):

ok i will but mind helping on couple more?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

no go ahead

OpenStudy (anonymous):

i mean "no i don't mind"

OpenStudy (anonymous):

find angle f |dw:1374717625709:dw|

OpenStudy (anonymous):

how do you know when to use cos-1 or any of those -1

OpenStudy (anonymous):

this one you don't even need a calculator for but we can do it that way too since \(\sin(f)=\frac{9}{18}=\frac{1}{2}\) then \(f=30\) degrees

OpenStudy (anonymous):

oh good question how do you know which one to use!

OpenStudy (anonymous):

in this case you only know two sides, although you could find the third one by pythagoras since you know the "opposite" side and the "hypotenuse" use \[\sin(f)=\frac{opp}{hyp}\] because it is the one you know

OpenStudy (anonymous):

then \(f=\sin^{-1}(\frac{1}{2})=30\)

OpenStudy (anonymous):

if you knew the "adjacent" side and the "hypotenuse" you would use cos and if you knew "opposite" and "adjacent" you would use tan

OpenStudy (anonymous):

if you know them all, you can take your pick, it won't make any difference which one you use

OpenStudy (anonymous):

ohh ok i get itso if i get all side but no degrees do i still use wichever??

OpenStudy (anonymous):

|dw:1374718070235:dw|

OpenStudy (anonymous):

there is a simple right triangle, a 3 - 4 - 5 right triangle suppose we want the angle i marked you could use \[\sin^{-1}(\frac{4}{5})\] or \[\cos^{-1}(\frac{3}{5})\] or \[\tan^{-1}(\frac{4}{3})\] you will get the same number for each

OpenStudy (anonymous):

ok i understand it so much better now thank you!

OpenStudy (anonymous):

yw you still got more or is that enough?

OpenStudy (anonymous):

i have more but i think i got it from here thanks

OpenStudy (anonymous):

ok good luck and post if you get stuck

OpenStudy (anonymous):

hey i have 8 questions i tried the but i failed idk why maybe im doing something wrong im sorry if its time consuming but mind helping i only ask because i need this test to pass a class in order to graduate !

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

it says to find the correct equation for |dw:1374719084567:dw|

OpenStudy (anonymous):

equation for the missing side? or an angle?

OpenStudy (anonymous):

sorry correct equation for triangle xyt

OpenStudy (anonymous):

a)cosT=xyt b)sinT=4/17 c)cosT=17/4 d)sinT=17/4

OpenStudy (anonymous):

those are the answer choices

OpenStudy (anonymous):

ok so we want to look at T

OpenStudy (anonymous):

i believe so

OpenStudy (anonymous):

you only have the two numbers 4 and 17 4 is the side "adjacent" to T and 17 is the hypotenuse

OpenStudy (anonymous):

\(\frac{adj}{hyp}\) is cosine so \[\cos(T)=\frac{4}{17}\]

OpenStudy (anonymous):

ohhh ok i get it

OpenStudy (anonymous):

theirs one similar but it has 3 numbers

OpenStudy (anonymous):

actually, however, all your answer choices are wrong

OpenStudy (anonymous):

b)sinT=4/17 is wrong because it should be cosine and not sine

OpenStudy (anonymous):

c)cosT=17/4 is wrong because it should be \(\frac{4}{17}\)

OpenStudy (anonymous):

sorry i typed it wrong it was a)cosT=4/17

OpenStudy (anonymous):

d)sinT=17/4 is way off

OpenStudy (anonymous):

oooh okay, then that is correct

OpenStudy (anonymous):

you got another?

OpenStudy (anonymous):

yes if you dont mind i have 5 more similar to this

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