Question

At a family gathering, 28 people are trying to fit into several cars. Your car holds 6 people. How many different groups of 6 could you take in your car?

Answer 1

@mebs hey u should help me out

Answer 2

This would be a combination problem: 28 choose 6

Answer 3

but then wouldn't that be like 27*27*26.... divided by 6*5*4*???

Answer 4

or just like 28*27*26*25*24*23???

Answer 5

\[\frac{28!}{6!(28-6)!}\]

Answer 6

so wait sorry how would u do that

Answer 7

it would be 28/ 6! 22! ???

Answer 8

*28!

Answer 9

yes

Answer 10

ok thank u

Answer 11

yw

Answer 12

what abt this?
Determine whether the scenario below involves permutations or combinations.

A group of seven actors are competing to earn one of three roles in a TV show: Michael, George, and Oscar. How many unique arrangements are possible?

Answer 13

I would say it is a combination because the order the 3 are chosen does not matter.

Answer 14

so just 3*2*1

Answer 15

How many actors are there?

Answer 16

3

Answer 17

A group of seven actors

Answer 18

oh sorry I was thinking of the roles

Answer 19

How many actors are there?

Answer 20

7..

Answer 21

How many will be chosen?

Answer 22

3

Answer 23

Then how about 7 choose 3 ?

Answer 24

so...
7! / 3!(7-3)! ?

Answer 25

yes

Answer 26

Except that the problem only says is it a permutation or a combination.

Answer 27

well no its asks how many unique arrangements are possible?

Answer 28

AND I just FORGOT how I type this into my calc D:

Answer 29

7! divided by 3 ! divided by 4!

Answer 30

why is it 3! divided by 4! now?

Answer 31

Because 7-3 is 4

Answer 32

oh :p right

Answer 33

so 35

Answer 34

That's what I got.

Answer 35

ok thank u

Answer 36

yw