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Mathematics 14 Online
OpenStudy (anonymous):

the table shows the probabilities of the number of dvds in a house based on information gathered through a survey. # of dvds=0 1 2 3 4 or more probability=.05 .24 .33 .21 .17 find the probability of a house having fewer than 2 dvds

OpenStudy (kropot72):

The required probability is found by adding together the probabilities of 0 dvds and 1 dvd: P(fewer than 2 dvds) = 0.05 + 0.24 = ?

OpenStudy (anonymous):

so the answer is .29?

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