Question

sd

Answer 1

4/5

Answer 2

\[\sqrt{(\frac{ 3^2 }{ 5^2 })+(b^2)} = 1\]
Since P is in quadrant, b must be positive.
Solve for b
\[\frac{ 9 }{ 25 } + b^2 = 1\]
\[b^2 = \frac{ 16 }{ 25 }; b = \frac{ 4 }{ 5 }\]

Answer 3

Oops! Quadrant 2 means that b is negative! The answer is b = -4/5

Answer 4

kk

Answer 5

thanks

Answer 6

np