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Mathematics 11 Online
OpenStudy (anonymous):

The number of moles of CaCl2 needed to react with excess AgNO3 to produce 4.13gm of AgCl

OpenStudy (ankit042):

CaCl2+2AgNO3-> 2AgCl + Ca(NO3)2 this is the right balanced equation

OpenStudy (unklerhaukus):

comparing the stoichiometric ratios, we see one mole of calcium chloride will form 2 moles of silver chloride,

OpenStudy (anonymous):

Thanks ankit could u help solving I know the equation

OpenStudy (anonymous):

Yes then

OpenStudy (unklerhaukus):

how many moles of silver chloride is 4.13gm ?

OpenStudy (ankit042):

can you calculate the mass of all compounds

OpenStudy (ankit042):

find the moles of AgCl and then using stoichiometric ratios you will reach the answer

OpenStudy (anonymous):

I have found the molar masses .. Now the moles?

OpenStudy (anonymous):

Got it thanx

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