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The number of moles of CaCl2 needed to react with excess AgNO3 to produce 4.13gm of AgCl
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CaCl2+2AgNO3-> 2AgCl + Ca(NO3)2 this is the right balanced equation
comparing the stoichiometric ratios, we see one mole of calcium chloride will form 2 moles of silver chloride,
Thanks ankit could u help solving I know the equation
Yes then
how many moles of silver chloride is 4.13gm ?
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can you calculate the mass of all compounds
find the moles of AgCl and then using stoichiometric ratios you will reach the answer
I have found the molar masses .. Now the moles?
Got it thanx
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