Find the length of the midsegment. http://gyazo.com/03d6de82fb7a7d15d249f1056f864174
This is the theorem you need: The segment joining the midpoints of two sides of a triangle (known as midsegment) has length half that of the third side of the triangle.
5x + 2 = (1/2)* (3x + 32) @GeometryHelpPlz
22
To help you get started, multiply both sides by 2 to clear the fractions. 5x + 2 = (1/2)* (3x + 32) 2(5x + 2) = 3x + 32 10x + 4 = 3x + 2 And, then ...
Let me see if I get 22.
10x+4=3x+2 so 13x=6?
I messed this up by deleting a 2. 5x + 2 = (1/2)* (3x + 32) 2(5x + 2) = 3x + 32 10x + 4 = 3x + 32 --> not just 2 x = 4 so the midsegment is 22 as you posted earlier.
Oh okay you put it way beter than they did thanks !
Alrighty, then. You are welcome.
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