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OpenStudy (anonymous):

How many electrons needed for the reduction of each mole of Cr in the reaction CrO5+H2SO4 ----- Cr2(SO4)3 + h2O + O2 Answer is 3

OpenStudy (anonymous):

The first reagent should be Cr2O5, I think, and this would be calculated via electron balance. Inital charge of Cr is +5, final charge is +3 so it received 2 electrons for each atom, 4 total, if I'm not wrong.

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