problem below (dealing with radicals)
\[\frac{ \sqrt{75x^5y^2} }{ \sqrt{3xy} }\]
The numerator can have terms moved outside the radical sign by taking their square root. For example 75 can be factored into 25 * 3, where the square root of 25 is 5. By doing this the numerator changes as follows: \[\sqrt{75x ^{5}y ^{2}}=5\sqrt{3x ^{5}y ^{2}}\] Can you see how the powers of the terms in x and y in the numerator can be reduced by this approach?
the it would be \[5x^2y \sqrt{3x}\] ?
Good work! You are correct. So now we have \[\frac{5x ^{2}y \sqrt{3x}}{\sqrt{3xy}}\] So what will we have if the numerator and the denominator are both divided by \[\sqrt{3x}\]
\[\frac{ 5x^2y }{ \sqrt{y} }\] i duno?
Yes, you are correct. Finally divide the numerator and denominator by the square root of y so the answer is a single expression, not a quotient.
so \[5x^2\sqrt{y}\]
Excellent. You have got it. Good work!
thanks
You're welcome :)
thank u
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