Question

f

Answer 1

@primeralph

Answer 2

Hint:
\[\huge \angle 1 =\angle 2\]

Answer 3

\[\huge 8y-6=7y\]
solve for y?

Answer 4

@MayMay_69

Answer 5

what is the value of y?

Answer 6

\[\huge 8y-6=7y\]
then add -6 to both sides,
\[\huge 8y-6+6=7y+6\]
then subtract 7y to both the sides,
\[\huge 8y-7y=6\]
\[\huge y=6\]

Answer 7

so angle 2
\[\huge \angle 2=7y\]
put y=6 , we get
\[\huge \angle2=7 \times 6=42^ \circ\]

Answer 8

so option d is right answer

Answer 9

hope you understand. @MayMay_69

Answer 10

good