Please Help!(: Find the point on the line 2 x + 5 y - 7 =0 which is closest to the point ( -7, -7 ).
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so the line contains (-7,-7) has the slope of 5/2. you know why? because it's perpendicular to the given line. (We are asked to find the closest gap, that means the perpendicular line) you have slope m = 5/2, you have point (-7,-7), just plug into the formula y = m +b to find out the equation of the line. NOT finish yet. let those line equal, solve for the intersection point, and apply distance formula to find out the distance between the point (-7,-7) and the intersection point ha!! my solution is so bad, but I don't know any simpler way. Good luck
\[y=\frac{ 5 }{ 2 }x+\frac{ 5 }{ 2 } ?\]
I don't know, just give you method, carefully calculate is yours
expand a circle centered at -7,-7 until it hits the stated line :) \[f(x,y) =(x+7)^2+(y+7)^2~:~g(x,y)=2x+5y-7 \] \[fx=2(x+7)~:~k~gx=2k~:~x=k-7\] \[fy=2(y+7)~:~k~gy=5k~:~y=\frac52k-7\] plug x and y into g to solve for k \[0=2(k-7)+5(\frac52k-7)−7\] \[7=2k-14+\frac{25}2k-35\] \[56=\frac{29}2k\] \[\frac{112}{29}=k\] therefore (if i dint mess up) \[x = \frac{112}{29}-7\] \[y=\frac52\frac{112}{29}-7\]
http://www.wolframalpha.com/input/?i=%28x%2B7%29%5E2%2B%28y%2B7%29%5E2%3D3136%2F29%2C+2x%2B5y%3D7
Ohhhh! okay. that made more sense! the whole g(x,y) and k got me a bit confused though... @amistre64
it was over kill to say the least ... but i needed some lagrange multiplier practice. we could have just as well made an oversized circle; found the points of intersection and midpointed them
Well. thank you! (: Over-all it was easy to follow along. @amistre64
youre welcome
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