Remainder Theorem. Find the value of K

1.) x^4 + kx^3+5x^2 - 5x - 8 / x + 2
r= -2

2.) 4x^6 - 5x^5 + 2x^4 - kx^3 + 3x^2+x - 4 - 4x+3
r= 2

Please explain :) Thankyou

Question

Remainder Theorem. Find the value of K 

1.) x^4 + kx^3+5x^2 - 5x - 8 / x + 2
r= -2

2.) 4x^6 - 5x^5 + 2x^4 - kx^3 + 3x^2+x - 4 - 4x+3 
r= 2

Please explain :) Thankyou

anonymous · Answer

r is the remainder?

anonymous · Answer

the second polinomial is divided by what?

anonymous · Answer

Opps..Late correction..
2.) 4x^6 - 5x^5 + 2x^4 - kx^3 + 3x^2+x - 4 / 4x+3 
r= 2

loser66 · Answer

if you replace x = -2 into the first equation, what do you get?

loser66 · Answer

I am guiding you to understand the problem. Not for fun

anonymous · Answer

(-2)^4 + k(-2)^3+5(-2)^2 - 5(-2) - 8 ??

loser66 · Answer

yes , let it = r =2 to solve for k
that the way to do

loser66 · Answer

* r= -2