Question

The roots of 2kx^2+6 = x^2+8x are equal what is the value of k?

Answer 1

hint :
D = 0
with D = b^2 - 4ac

Answer 2

why D?

Answer 3

pls teach me

Answer 4

@RadEn

Answer 5

that's the rule if the roots are same then the value of discriminant must be equal 0

Answer 6

pls write the solution :)

Answer 7

first given
2kx^2+6 = x^2+8x
subtract on both sides by (x^2+2x), we get
2kx^2+6 - (x^2+8x) = x^2+2x - (x^2+2x)
2kx^2+6 - x^2- 8x = 0
(2k - 1)x^2 - 8x + 6 = 0

looks that the value of a = 2k-1, b = -8, and c = 6
now D = 0
b^2 - 4ac = 0
(-8)^2 - 4 * (2k - 1)(6) = 0
64 - 48k + 24 = 0
solve for k

Answer 8

thanks :)

Answer 9

welcome :)

Answer 10

k= 11/6? am I right?

Answer 11

@RadEn am I right? correct answer 11/6?

Answer 12

64 - 48k + 24 = 0
88 - 48k = 0
88 = 48k
k = 88/48 = 11/6

you are right :D

Answer 13

THANK YOU VERY MUCH :D

Answer 14

my pleasure can help :D