Question

Find the thirtieth term of the following sequence.

-6, -4, -2, 0, ...


52
64
66

Answer 1

First, you must find the number series that those numbers follow. Do you know how to find this?

Answer 2

Nope, im jus tryina do my work soo i can go home nd have a good B-Day

Answer 3

whats the difference between a -6 and a -4?
difference between -4 and -2 ?
difference between -2 and 0 ?

Answer 4

+2

Answer 5

Happy birthday! I'll make it a simple version then. To find the number series expression, you must find the difference between each number, which in this case is 2.
Now the beginning value is -6, so (something)+2n (n being the number of the term in the series.
To find what the (something) is, you plug 1 in for n and solve, setting it equal to the first term: x+2(1)=-6
x=-8
So your beginning number of the number series is -8, and the difference between each number is +2, so the number series looks like this: x=-8+2n.

Answer 6

the formula is : an = a1 + (n - 1) * d
a1 is first term = -6
n = the term you want to find = 13
d = the difference between the numbers = 2
now plug all your stuff into the formula

Answer 7

Soo thebanswer is?....., im guessing 64?

Answer 8

the answer**

Answer 9

x=-8+2n. Plug 30 in for n and solve.

Answer 10

Okk & Ty

Answer 11

a13 = -6 + (13 - 1) * 2
a13 = -6 + 12 * 2
a13 = -6 + 24
a13 = 18 <-- 13th term

are you looking for the 13 term or the sum ?

Answer 12

It's the 30th term.

Answer 13

oh...my bad.....I feel stupid now

Answer 14

Don't worry. I read it as 13th too at the beginning...

Answer 15

Happy Birthday @LaDarriusWatson

Answer 16

Ty ;)

Answer 17

Im jus turning 16

Answer 18

sorry about the mess up I made on your question......16th birthday....hmmm...don't party too hard ...lol

Answer 19

Lmao