Question

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I WILL AWARD MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Solve Log(2)3 + Log(2)x=3

Answer 1

@Hero @primeralph @satellite73

Answer 2

@thomaster

Answer 3

@countonme123 @Courage.

Answer 4

Is the 2 in both logs a subscript?

Answer 5

YEs

Answer 6

\[\log _{2}3+\log _{2}x=3\]
That's how the equation looks right?

Answer 7

Yes

Answer 8

My time limit is about to end please help me.

Answer 9

You should end up with \[\log _{2}3x=3\]
Do you have answer options?

Answer 10

NO.

Answer 11

Just solve it. PLEASE I HAVE ONLY @ MINUTERS TO FINISH QUESTION PLEASE HELP <E/

Answer 12

<_- ->

Answer 13

\[\log _{2}x=1\]

Answer 14

Thanks you.

Answer 15

So x=2

Answer 16

Can you solve this one also\[8=3^(2x+2)\]

Answer 17

PLEASE I KNOW I AM PUTING PRESSURE BUT PLEASE HELP ME. PRETEND YOU ARE IN A MATH COMPERRITION.

Answer 18

@phi @Math81

Answer 19

8=6x+6
-6x=6-8
-6x=-2
x=-1/3

Answer 20

show some work please. Like the first one that is good.

Answer 21

Yes thank you SOOOOO MUCH.

Answer 22

I need help with nly one more. PLEASE

Answer 23

Write in simplest form

Answer 24

\[\frac{ 2logx+logy }{ 3logz }\]

Answer 25

OK thank you so much.

Answer 26

for \[ \log _{2}3+\log _{2}x=3 \]
use this rule
\[ \log(a) + \log(b)= \log(a\cdot b) \]
you get
\[ \log_2(3x) = 3\]
make these the exponents of 2
\[ 2^{ \log_2(3x) } = 2^3 \]
the left side simplifies to 3x
\[ 3x = 8 \]
solve for x
\[ x = \frac{8}{3} \]

Answer 27

Oh shoot, you're right. I can't believe I missed that

Answer 28

NOw he is correct. I got every single question with you incorrect.

Answer 29

this is good until the last line
8=6x+6
-6x=6-8
-6x=-2
x=-1/3 <--- this should be -2/-6 which simplifies to +1/3 (two minuses make a plus)