how long will it take $10,000 invested at 5% compounded continuously to grow to $25,000?
(10000) * (1.05^x) = 25000. Solve for x.
thank you
from where you got 1.05?? the percentage is 0.05^x
Continuous Compound Formula: \[A = Per^t\] A=Account Balance = 25,000 P=Principal = 10,000 r=rate (decimal form) = 0.05 t=time (in years) = what you need to find \[25,000 = 10,000e^{(0.05)t}\]
In order to solve this, you will eventually, have to take logs. For now, start by dividing both sides by 10,000
\[\frac{25000}{10000} = e^{(0.05)t}\]\[2.5 = e^{(0.05)t}\]
Next, take logs of both sides: \[\log(2.5) = \log(e^{(0.05t)})\] \[log(2.5) = t\log(e^{0.05})\]
i divided 25,000/10,000 = 10,000e(0.05)t/10,000 = 2.5=1.0512t both side divided by 1.0512 t=2.4
\[\frac{\log(2.5)}{\log(1.051271)} = t\]
ok
We're using logs..so please remember that
i punch it in the calculator and i got 18.33 for t
Good job
thanks to you
If you use my formula, you get the most precise result.
If you use virgil's formula, you still get 18, but you get the wrong approximation of months.
yeah but i am really dumb when it come to logs and logarithm
Well, there are some things you can do to make your life easier. My rule is to "only take logs when you need to".
i will follow that too thank you
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