Write the equation of the line passing through the points (0, -4) and (-2, 2).
you already have the y-int (0,-4) all you need to write the equation is the slope use the slope formula
Remember that slope for 2 points (a,b) and (c,d) is \[\frac{ c-a }{ d-b }\]
So the slope for (0,-4), (-2,2) is \[\frac{ 0--2 }{ -4-2 }=\frac{ 2 }{ -6 }=-\frac{ 1 }{ 3 }\]
Now, point (0,-4) is the y-intercept of the equation.
Just like ivettef365 said, you use the slope formula, which is \[y=mx+b\] where m is the slope and b is the y-intercept.
plug in -1/3 for m and 3 for b, and you'll get \[y=-\frac{ 1 }{ 3 }x-4\]
no, the slope is y2 - y1 ------ x2 - x1 2 - (-4) 6 ------- = ------ = -3 -2 -0 -2
Oops. You're right. My mistake. So the equation would be y=-3x-4
the equation is y = -3x -4
Thank you for correcting me.
your welcome
Thanks guys!!(:
yw :)
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