What is the value of x to the nearest tenth?
A. 9.6
B. 12.8
C. 20.8
D. 8.0
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OpenStudy (anonymous):
OpenStudy (anonymous):
I think the answer is D?
OpenStudy (jasmineflvs):
what kind of problem is it and i can give you a hint how to figure it out
OpenStudy (anonymous):
what do you mean??
OpenStudy (jasmineflvs):
what area is this problem in?
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OpenStudy (anonymous):
i dunno
OpenStudy (jasmineflvs):
lol
OpenStudy (anonymous):
So first you have to see that the answer has to be half of 25.6.
What is half of 25.6?
OpenStudy (anonymous):
12.8
OpenStudy (anonymous):
Thats the answer then (:
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OpenStudy (anonymous):
are you sure?
OpenStudy (anonymous):
Positive (:
OpenStudy (anonymous):
oh ok thanks
OpenStudy (anonymous):
actually no hold on
OpenStudy (anonymous):
Its 8.0 sorry!
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OpenStudy (anonymous):
that's fine :)
OpenStudy (anonymous):
Good Luck!
OpenStudy (anonymous):
thank you :)
OpenStudy (anonymous):
yw
OpenStudy (jdoe0001):
@ehmuleeee still there?
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OpenStudy (anonymous):
yesss
OpenStudy (jdoe0001):
|dw:1374791602143:dw|
OpenStudy (jdoe0001):
if you take a peek at the "2 triangles" the smaller inside and the bigger containing it
the opposite side for the bigger is the "correspondent" to the "x" in the smaller one
using pythagorean theorem the opposite side of the bigger triangle will be
\(\bf c^2 = a^2 + b^2 \implies \sqrt{c^2-a^2} = b^2\)
OpenStudy (jdoe0001):
thus the 16 units UP are really just the radius, the other line going down from it, would also be the radius and is thus 16 too, so the "c" side is really 16+16 = 32, "a" is 25.6
thus
\(\bf b = \sqrt{32^2-25.6^2} \implies 19.2\)
OpenStudy (jdoe0001):
|dw:1374791967480:dw|
the just solve for "x"
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