75 packages are randomly selected from packages recieved by a parcel service. the sample has a mean weight of 10.2 pounds and a standard deviation of 2.9 pounds. what is the 95 percent confidence interval for the true mean weight, mu, of all the packaes recieved by the parcel service

Question

calculusfunctions · Answer

@muffin89 the 95% confidence interval for a mean will be found by$$\mu \pm 1.96\frac{ \sigma }{ \sqrt{N} }$$where of course N will be the # of packages in this instance.

HOPE THIS HELPS!!

anonymous · Answer

Splendid! Thank you!