Question

What is the maximum # of squares with an are of 18 that can fit inside a circle with radius 6 if the squares interiors cannot overlap

Answer 1

@Mertsj @Loser66 @blurbendy

Answer 2

I think 4 since the diagonal of the square would be equal to the radius.

Answer 3

4 is my guess too, just based on the approx side length of the square.

Area 18 means the side is sqrt18, so the diagonal is 6 as mertsj said.

Answer 4

\[\large Area = 18 = s^2\] (s being the side length of the square)

so \[\large s = \sqrt{18}\]

The diagonal of the square is found by pythag:

\[\large s^2 + s^2 = d^2\] (d for diagonal)

\[\large \sqrt{18}^2 + \sqrt{18}^2 = d^2\]
\[\large d^2 = 36\]
so d=6.

Answer 5

Yes. And 6 is the radius of the circle.

Answer 6

oh okay what about if "how many circles with radius of 1 can fit inside a square with an area of 16 without the circles interiors overlapping?"

Answer 7

4 again

Answer 8

Find the side length of the square... area 16 means side is 4.

Use diameter of the circle: diameter will be 2.