Question

Two end points of a line segment are (2, 8) and (-4, -8). What are the coordinates of the point on the line through which its bisector passes?

(5, -6)

(3, 8)

(-2, 0)

(-1, 0)

Answer 1

I think its B

Answer 2

@melody16 you think you can help me lol :$

Answer 3

The bisector passes through the midpoint. Here is the midpoint formula:
\[(\frac{x _{1}+x _{2}}{2},\frac{y _{1}+y _{2}}{2})\]

Answer 4

\[\left( \frac{ 2+(-4) }{ 2 } \right)+\left(\begin{matrix}\frac{ 8+(-8) }{ 2 } \\ \end{matrix}\right)\]

Answer 5

, not +

Answer 6

Simplify

Answer 7

\[\left(\begin{matrix}\frac{ -2 }{ 2} \\ \end{matrix}\right), 2\]

Answer 8

\[(\frac{2+-4}{2},\frac{8+-8}{2})=(-1,0)\]

Answer 9

where does the -1 come from though

Answer 10

What is 2-4?

Answer 11

-2

Answer 12

What is -2/2 ?