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Mathematics 9 Online
OpenStudy (anonymous):

Solve the system by graphing. -x+y+2=0 -3x+3y=0

OpenStudy (anonymous):

1)y=x-2 3y=3x 2)y=x

OpenStudy (anonymous):

now graph it

OpenStudy (anonymous):

graph y=x

OpenStudy (anonymous):

do it

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

it didnt help

OpenStudy (anonymous):

whats the problem? heh?

OpenStudy (anonymous):

your no help

OpenStudy (skullpatrol):

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OpenStudy (skullpatrol):

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OpenStudy (skullpatrol):

Come on @Ashley_Cute you can do it if you try :-)

OpenStudy (anonymous):

Im sry but i don't know what to do thats y i asked the question

OpenStudy (skullpatrol):

No problem, just ask questions about what you don't understand.

OpenStudy (anonymous):

it says graph it but it is obviously not graphable and i need help making it graphable

OpenStudy (skullpatrol):

Why do you think y = x is not "graphable"?

OpenStudy (anonymous):

where did y=x come from

OpenStudy (skullpatrol):

$$ -3x+3y=0$$

OpenStudy (anonymous):

should i put them in y=mx+b and graph them like that

OpenStudy (skullpatrol):

Yes, y = x is a special case of y = mx + b for m =1 and b = 0.

OpenStudy (anonymous):

3y=-3x

OpenStudy (skullpatrol):

add 3x to both sides of -3x + 3y = 0

OpenStudy (anonymous):

i thought we were putting it in y=mx+b form

OpenStudy (skullpatrol):

We are, y = 1*x + 0

OpenStudy (anonymous):

okay so -3x+3y=0 which value am i trying to isolate first

OpenStudy (anonymous):

@skullpatrol

OpenStudy (skullpatrol):

You want the y = mx + b form... -3x+3y=0 3y = 3x y = x

OpenStudy (anonymous):

o lol we divided by 3 and they canceled

OpenStudy (skullpatrol):

Yes, the idea is balance whatever you do on one side do it to the other, just like a weight balance.

OpenStudy (anonymous):

lol sry i took so much of your time thx your nice

OpenStudy (skullpatrol):

So can you graph it now?

OpenStudy (skullpatrol):

@Ashley_Cute is it "graphable"?

OpenStudy (anonymous):

yes

OpenStudy (skullpatrol):

Use the same method on the second equation: -x+y+2=0

OpenStudy (anonymous):

kk

OpenStudy (skullpatrol):

y = mx + b form

OpenStudy (anonymous):

y=-x+2 right

OpenStudy (skullpatrol):

No, both signs are opposite.

OpenStudy (anonymous):

?????

OpenStudy (skullpatrol):

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