Mathematics
9 Online
OpenStudy (anonymous):
Solve the system by graphing.
-x+y+2=0
-3x+3y=0
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OpenStudy (anonymous):
1)y=x-2
3y=3x
2)y=x
OpenStudy (anonymous):
now graph it
OpenStudy (anonymous):
graph y=x
OpenStudy (anonymous):
do it
OpenStudy (anonymous):
okay
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OpenStudy (anonymous):
it didnt help
OpenStudy (anonymous):
whats the problem? heh?
OpenStudy (anonymous):
your no help
OpenStudy (skullpatrol):
|dw:1374805873483:dw|
OpenStudy (skullpatrol):
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OpenStudy (skullpatrol):
Come on @Ashley_Cute you can do it if you try :-)
OpenStudy (anonymous):
Im sry but i don't know what to do thats y i asked the question
OpenStudy (skullpatrol):
No problem, just ask questions about what you don't understand.
OpenStudy (anonymous):
it says graph it but it is obviously not graphable and i need help making it graphable
OpenStudy (skullpatrol):
Why do you think y = x is not "graphable"?
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OpenStudy (anonymous):
where did y=x come from
OpenStudy (skullpatrol):
$$ -3x+3y=0$$
OpenStudy (anonymous):
should i put them in y=mx+b and graph them like that
OpenStudy (skullpatrol):
Yes, y = x is a special case of y = mx + b for m =1 and b = 0.
OpenStudy (anonymous):
3y=-3x
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OpenStudy (skullpatrol):
add 3x to both sides of -3x + 3y = 0
OpenStudy (anonymous):
i thought we were putting it in y=mx+b form
OpenStudy (skullpatrol):
We are, y = 1*x + 0
OpenStudy (anonymous):
okay so -3x+3y=0 which value am i trying to isolate first
OpenStudy (anonymous):
@skullpatrol
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OpenStudy (skullpatrol):
You want the y = mx + b form...
-3x+3y=0
3y = 3x
y = x
OpenStudy (anonymous):
o lol we divided by 3 and they canceled
OpenStudy (skullpatrol):
Yes, the idea is balance whatever you do on one side do it to the other, just like a weight balance.
OpenStudy (anonymous):
lol sry i took so much of your time thx your nice
OpenStudy (skullpatrol):
So can you graph it now?
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OpenStudy (skullpatrol):
@Ashley_Cute is it "graphable"?
OpenStudy (anonymous):
yes
OpenStudy (skullpatrol):
Use the same method on the second equation: -x+y+2=0
OpenStudy (anonymous):
kk
OpenStudy (skullpatrol):
y = mx + b form
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OpenStudy (anonymous):
y=-x+2 right
OpenStudy (skullpatrol):
No, both signs are opposite.
OpenStudy (anonymous):
?????
OpenStudy (skullpatrol):
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